Question

A Bowling ball is rolled down the alley with the constant velocity of 1.6 m/sec at an angle of 85° to the starting line, the position of the person throwing a bowling ball can be represented by the point (0,0). where is the ball after six seconds?

Answer 1

(0.8,9.6)

Explanation:

x=1.6*cos85* 6=0.8

y=1.6*sin85 *6=9.6

Answer 2

We have been given that a Bowling ball is rolled down the alley with the constant velocity of 1.6 m/sec at an angle of 85° to the starting line, the position of the person throwing a bowling ball can be represented by the point (0,0).

We are asked to find the position of ball after 6 seconds.

We will use horizontal position and vertical position formula to solve our given problem.

Horizontal position is given by formula:
`x=v\cdot \text{cos}(\theta)\cdot t` and vertical position is given by formula:
`y=v\cdot \text{sin}(\theta)\cdot t`,where,

v = Velocity,

t = Time,

`\theta` = Angle to the starting line.

For our given problem
`v=1.6`,
`t=6` and
`\theta=85^(\circ)`.

`x=1.8\cdot \text{cos}(85^(\circ))\cdot 6`

`x=10.8 \cdot 0.087155742748`

`x=0.9412820216784\approx 0.94`

`y=1.8\cdot \text{sin}(85^(\circ))\cdot 6`

`y=10.8\cdot 0.996194698092`

`y=10.7589027\approx 10.76`

Therefore, the position of ball after 6 seconds would be
`(0.94,10.76)`.