Question

Any help someone....
(solve triangles using the law of sines)

Answer 1

`B=51`°

Explanation:

Use the Law of Sines as follows:

`(sinC)/(c) =(sinB)/(b)`

Insert the appropriate values:

`(sin100)/(14) =(sinB)/(11)`

Isolate B. Multiply both sides by 11:

`11*((sin100)/(14) )=11*((sinB)/(11))\\\\(11*sin100)/(14) =sinB\\\\sinB=(11*sin100)/(14)`

Use the inverse:

`B=sin^(-1)((11*sin100)/(14))`

Insert the equation into a calculator and round to the nearest degree:

`B=50.7\\\\B=51`

Angle B is 51°.

:Done