7.6k views
2 votes
You have a standard deck of cards. The deck has 52 total cards and contains 4 suits: hearts, clubs, diamonds, and spades. Each suit consists of cards numbered 2-10, a jack, a queen, a king, and an ace.

You select one card at random from the deck. Let A be the event that the randomly selected card is a diamond and let B be the event that the card is a king. Based on this information, answer the following questions.

You have a standard deck of cards. The deck has 52 total cards and contains 4 suits-example-1
User Katstevens
by
8.2k points

2 Answers

6 votes

Answer:

1/4

1/13

1/52

Yes, events a and b are independent events

User Malus Jan
by
9.0k points
4 votes

Answer:


P(A) = (1)/(4)\\P(B) = (1)/(13)\\P(A \cap B) = (1)/(52)\\P(A/B) = (1)/(4)\\P(A/B) = P(A)\\

A and B are not independent events.

Explanation:

Total number of possibilities is 52 (Total number of cards in the deck).

Formula for probability of an event E can be observed as:


P(E) = \frac{\text{Number of favorable cases}}{\text {Total number of cases}}

For event A, number of cases possible for a card to be diamond = 13


P(A) = (13)/(52) \\\Rightarrow P(A) = (1)/(4)

For event B, number of cases possible for a card to be a king = 4


P(B) = (4)/(52) \\\Rightarrow P(B) = (1)/(13)

For the event,
A \cap B, the card is a king and diamond, only one case is possible.

Because there is only one card for king of diamond.


P(A \cap B) = (1)/(52)

Formula for P(A/B):


P(A/B) = (P(A \cap B))/(P(B))


\Rightarrow ((1)/(52))/((1)/(13))\\\Rightarrow (1)/(4)

Yes, P(A) is same as P(A/B).

Here, A and B are not independent events because they have a common case i.e. a king is there which is of diamond in the deck.

User Vizmi
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.