Question

What is the equation of the line passing through ( -5, -3 ) and perpendicular

to the line representing the equation y = - 5/7x + 2?

Answer 1

y = 7/5x + 4

Explanation:

use the slope from the equation -5/7 and take the negative reciprocal to get the perpendicular slope = 7/5. Then use the equation y=mx+b. Plug in x and y from the point given and the new slope and solve for b.

(-3) = (7/5)(-5) + b, (-3) = -7 + b, add 7 to both sides. b = 4. Rewrite the equation now to be y = 7/5x + 4