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An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0 L tank?

User Papa Stahl
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1 Answer

3 votes

Answer:

1.2 atm

Step-by-step explanation:

Given data

  • Volume of the gas in the tank (V₁): 200.0 L
  • Pressure of ethylene gas in the tank (P₁): ?
  • Volume of the gas in the torch (V₂): 300 L
  • Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.


P_1 * V_1 = P_2 * V_2\\P_1 = (P_2 * V_2)/(V_1) = (0.8atm * 300L)/(200.0L) = 1.2 atm

User Maksym Ganenko
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