Question

What kind of interference will occur when 75- MHzMHz television signals arrive at your receiver directly from a distant station and meet waves from the station that are first reflected from a nearby airplane 124 mm directly above your receiver then reflected toward your receiver? Assume 12λ12λ change in phase of the signal upon reflection of the airplane. Assume your receiver and the station are a long distance appart and lie on the x-axis, and assume the airplane is directly above your receiver. Consider the difference in path lengths between the two waves.

Answer 1

The waves interfere destructively occur. The further explanation is given below.

Step-by-step explanation:

The transmissions almost commute with either the speed of light. So, use the following relation to calculate the wavelength of that same TV signal.

⇒ λ =
`(c)/(v)`

⇒ =
`(3* 10^(8)m/s )/(75 \ MHz((10^(6)Hz)/(1 \ MHz)))`

⇒ =
`4 \ m`

The variance in the route between both the 2 waves that approach the recipient is 248 m, also because wave passes 124 m two times. And then after the plane's reflective thinking the waves iteration adjustments by half.

⇒ Δ
`x` =
`(m+(1)/(2) )` λ

If the value of the above expression is a positive integer, the waves interfere constructively, as well as the waves disrupt destructively if they are integral multiples of the half. Caused by a change of step due to the reflection the component of half would be added.

⇒
`248 \ m=(m+(1)/(2))(4 \ m)`

⇒
`m = 61.5`

Since the value of m seems to be an integral multiple of the half.

Therefore, the waves interfere destructively