Question

At 25ºC, the average velocity of a hydrogen molecule is 1.92 x 103 m/s. What is the average velocity of a nitrogen molecule at the same temperature?

NEED WORK

Answer 1

V = 513.36m/s

Step-by-step explanation:

Temperature (T) = 25°C = (25 + 273.15) = 298.15K

Speed (V) = 1.92*10³m/s

According to kinetic theory of gases, the speed (v) of a molecule is

V= √(3RT / M)

V = speed or velocity

R = ideal gas constant = 0.082J/mol.K

T = temperature of the gas

M = molar mass

Molar mass of hydrogen molecule = 2.0g/mol

Molar mass of Nitrogen molecule = (2×14.0) = 28.0g/mol

Since they're in the same temperature

V1 / V2 = √(M2 / M1)

1.92×10³ / V2 = √(28 / 2)

1.92×10³ / V2 = √(14)

1.92*10³ / V2 = 3.74

1.92*10³ = 3.74V2

V2 = 1920 / 3.74

V2 = 513.36m/s

The velocity of Nitrogen molecule is 513.36m/s