Answer:
A. 2.24 yd
B. 53.67 yd²
C. 5.33 yd³
Explanation:
Here we have;
Height of the pyramid = 2 yd
Side length of pyramid base = 2 yd
Therefore, the slant height forms a right triangle with the height of the pyramid and half the base hence;
(Slant height)² = (2·yd)² + (2·yd/2)² = 4·(yd)² + (yd)² = 5·(yd)²
∴ Slant height = √5 yards = 2.24 yd
B. The surface area of the cube with one side open is found as follows;
Surface area of container cube = 5 × (2·yd)² = 20 yards²
The surface area of the pyramid = Base area + 1/2 perimeter of base × Slant height
Since the base is open, we have;
The surface area of the pyramid = 1/2 perimeter of base × Slant height
= 1/2 × (4 × (2·yd))×yd·√5 = 4·yd×yd·√5 = 4·√5·(yd)²
Hence total surface area of the planter = Surface area of container cube + surface area of the pyramid
total surface area of the planter = 20·yd² + 4·√5 yd² = 24·√5 yards²
C. The volume of concrete needed to make the planter is the volume of the cube concrete container less the volume of the inverted pyramid
Volume of the cube = 2 × 2 × 2 = 8 yd³
Volume of the inverted pyramid = 1/3 × Base area × Height
Volume of the inverted pyramid = 1/3 × 2 × 2 × 2 = 8/3 yd³
Therefore, volume of the concrete needed = 8 yd³ - 8/3 yd³ = 16/3 yd³ = 5.33 yd³.