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The activity of a radioactive material drops to 1/16 of its original value in 20 years. What is its half life?

User SiBrit
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1 Answer

2 votes

Answer: 5 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:


t=(2.303)/(k)\log(a)/(a-x)

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant = x

a - x = amount left after decay process =
(x)/(16)

a) for calculating k


20=(2.303)/(k)\log(x)/((x)/(16))


k=(2.303)/(20)\log{16}


k=0.138years^(-1)

b) for calculating half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.


t_{(1)/(2)}=(0.693)/(0.138years^(-1))


t_{(1)/(2)}=5years

Thus its half life is 5 years

User Abhishek Asthana
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