Answer: 5 years
Step-by-step explanation:
Expression for rate law for first order kinetics is given by:
![t=(2.303)/(k)\log(a)/(a-x)](https://img.qammunity.org/2021/formulas/physics/high-school/34336uhzgbxxst4voy5o2jexos3nnuq6xo.png)
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant = x
a - x = amount left after decay process =
![(x)/(16)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8e5ju4c08pdua5lm1jk0mnvx8pghqo9hw0.png)
a) for calculating k
![20=(2.303)/(k)\log(x)/((x)/(16))](https://img.qammunity.org/2021/formulas/physics/high-school/qm3pjeepbgc0p7wyx19oe9ge7xpjgozev9.png)
![k=(2.303)/(20)\log{16}](https://img.qammunity.org/2021/formulas/physics/high-school/zfwiogij3q92cxu811mcqmzp6znugoow27.png)
![k=0.138years^(-1)](https://img.qammunity.org/2021/formulas/physics/high-school/8y38xf8wxrfhz9p1joihk3n34ggdd279uu.png)
b) for calculating half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
![t_{(1)/(2)}=(0.693)/(0.138years^(-1))](https://img.qammunity.org/2021/formulas/physics/high-school/x66dsh7ns3m1uozp2pagjydy9bwl1sliy1.png)
![t_{(1)/(2)}=5years](https://img.qammunity.org/2021/formulas/physics/high-school/xmzkauvduzjw07ymse063mvfuznvpk59bf.png)
Thus its half life is 5 years