Question

The pressure and temperature inside a bike tire is 10 atm and 10k respectively. What will the pressure become in the tire when the temperature is increased 20k

Answer 1

`P_2=20atm`

Step-by-step explanation:

Hello,

In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior as a directly proportional relationship:

`(P_1)/(T_1)= (P_2)/(T_2)`

Thus, we solve for the final pressure P2 to obtain it as shown below:

`P_2=(P_1T_2)/(T_1)=(10atm*20K)/(10K) \\\\P_2=20atm`

Hence, we notice that the temperature doubles as well as the pressure.

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