Question

In this circuit the battery provides 3 V, the resistance R1 is 7 Ω, and R2 is 5 Ω. What is the current through resistor R2? Give your answer in units of Amps. An Amp is 1 Coulomb of charge flowing through a cross-sectional area of the wire per second - that's a lot of charge per second and will warm up a typical wire quite a bit! Most devices have circuits with larger resistors - kLaTeX: \OmegaΩ (103 LaTeX: \OmegaΩ) and MLaTeX: \OmegaΩ (106 LaTeX: \OmegaΩ) are common.

Answer 1

The current pass the
`R_2` is
`I = 0.25 A`

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The voltage is
`V = 3V`

The first resistance is
`R_1 = 7 \Omega`

The second resistance is
`R_2 = 5 \Omega`

Since the resistors are connected in series their equivalent resistance is

`R_(eq) = R_1 +R_2`

Substituting values

`R_(eq) = 7 + 5`

`R_(eq) = 12 \Omega`

Since the resistance are connected in serie the current passing through the circuit is the same current passing through
`R_2` which is mathematically evaluated as

`I = (V)/(R_(eq))`

Substituting values

`I = (3)/(12)`

`I = 0.25 A`