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In ΔPQR, ∠P and ∠Q are complementary angles.

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User Pcu
by
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2 Answers

9 votes

Answer:

P + Q = 90

P = 90 - Q

Cos (p) = cos (90-Q) = sinQ = 4/5 (given)

You can find CosQ from the triangle of Q

CosQ = sqrt (5^2 - 4^2) / 5 = 3/5

Required = CosP + CosQ = 4/5 + 3/5 = 7/5

Explanation:

User Nathan Kidd
by
8.2k points
9 votes

Answer:

P + Q = 90

P = 90 - Q

Cos (p) = cos (90-Q) = sinQ = 4/5 (given)

You can find CosQ from the triangle of Q

CosQ = sqrt (5^2 - 4^2) / 5 = 3/5

Required = CosP + CosQ = 4/5 + 3/5 = 7/5

Explanation:

hope this helps if not please let me now

User Ntropy Nameless
by
8.3k points

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