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Circle centered at (0,−4) with a radius of 3

User Gaz Smith
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Answer:

Circle centered at (0,−4) with a radius of 3.

It has equation form as: x^2 + (y + 4)^2 = 3^2.

User Franz Payer
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Answer: since the center is (0,-4) and have a radius of 3 then the standard form of an equation of a circle will be (x-0)^2+(y-(-4))^2=9 or 3^2. the formula of the standard form is (x-h)^2+(y-k)^2=r^2 where the center is (h,k).

The general form will be x^2+y^2+8y+7=0

Explanation:

User Daulex
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