Answer:
x=1, y=3
Explanation:
using sublimation method
y-3x=0 ....eqn(1)
2y+5x=11....eqn(2)
from eqn 1
y-3x=0
y=3x
substitute y=3x into eqn 2
2y+5x=11
2(3x)+5x=11
6x+5x=11
11x=11 (divide both sides by the coefficient of x)
x=1
since x=1 , substitute x=1 into eqn 1 to get y
y-3x=0
y-3(1)=0
y-3=0
y=3
Using elimination method
y-3x=0....eqn (1)
2y+5x=11....eqn (2)
multiply eqn 1 through by 2 and eqn 2 through by 1 to eliminate y
2y-6x=0.... eqn 3
2y+5x=11.... eqn 4
subtract eqn 4 from from eqn 3
-11x=-11 (divide both sides by the coefficient of x)
x=1
substitute x=1 into eqn 2 to get y
2y+5x=11
2y+ 5(1) =11
2y+5=11
2y=11-5
2y= 6 (divide both sides by the coefficient of y)
y=3