Question

3.15 LAB: Countdown until matching digits

Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and stopping when both output digits are identical.

Ex: If the input is:

93
the output is:

93 92 91 90 89 88
Ex: If the input is:

77
the output is:

77
Ex: If the input is:

15
or any value not between 20 and 98 (inclusive), the output is:

Input must be 20-98.


#include

using namespace std;

int main() {

// variable

int num;



// read number

cin >> num;

while(num<20||num>98)

{

cout<<"Input must be 20-98 ";

cin>> num;

}



while(num % 10 != num /10)

{

// print numbers.

cout<
// update num.

num--;

}

// display the number.

cout<
return 0;

}




I keep getting Program generated too much output.
Output restricted to 50000 characters.

Check program for any unterminated loops generating output

Answer 1

See explaination

Step-by-step explanation:

n = int(input())

if 20 <= n <= 98:

while n % 11 != 0: // for all numbers in range (20-98) all the identical

digit numbers are divisible by 11,So all numbers that

​​​​​​ are not divisible by 11 are a part of count down, This

while loop stops when output digits get identical.

print(n, end=" ")

n = n - 1

print(n)

else:

print("Input must be 20-98")