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If r(x) = 3x -1 and s(x) = 2x + 1, which is equivalent to [r/s] (6)?
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If r(x) = 3x -1 and s(x) = 2x + 1, which is equivalent to [r/s] (6)?

User Jessica Gadling
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\text{Solve by turning it into a fraction and plugging in the value to x:}\\\\(3x-1)/(2x+1)\\\\(3(6)-1)/(2(6)+1)\\\\(18-1)/(12+1)\\\\(17)/(13)\\\\\text{You can't simplify the fraction any further, in which it'll conclude your answer}\\\\\boxed{(17)/(13)}

User Mohammad Nazari
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