Question

What volume in litres will 38gr of F2 occupy at 0.999 bar and 273 K

Answer 1

`V=22.68L`

Step-by-step explanation:

Hello,

In this case, we use the ideal gas equation to compute the volume as shown below:

`PV=nRT\\\\V=(nRT)/(P)`

Nonetheless we are given mass, for that reason we must compute the moles of gaseous fluorine (molar mass: 38 g/mol) as shown below:

`n=38 g *(x)/(y) (1mol)/(38 g) =1mol`

Thus, we compute the volume with the proper ideal gas constant, R:

`V=(1mol*0.083(bar*L)/(mol*K)*273K)/(0.999bar) \\\\V=22.68L`

Best regards.