Question

How many copper atoms are in a 70g copper

Answer 1

6.64x10^23 atoms.

Step-by-step explanation:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This implies that 1 mole of Cu also contains 6.02x10^23 atoms.

1 mole of Cu = 63.5g

If 63.5g of Cu contains 6.02x10^23 atoms,

Then 70g of Cu will contain = (70x6.02x10^23) /63.5 = 6.64x10^23 atoms.

Therefore, there are 6.64x10^23 atoms in 70g oh Cu

Answer 2

`x = 6.634* 10^(23)\,atoms`

Step-by-step explanation:

The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:

`x = \left((70\,g)/(63.546\,(g)/(mol)) \right)\cdot \left(6.022* 10^(23)\,(atoms)/(mol) \right)`

`x = 6.634* 10^(23)\,atoms`