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How many grams of NH3 are contained in 1.75 L of a .833 M NH3 solution?

1 Answer

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Answer:

24.9 g

Step-by-step explanation:

Given data

  • Volume of the solution: 1.75 L
  • Concentration of ammonia: 0.833 M

Step 1: Calculate the moles of ammonia

The concentration of ammonia is 0.833 M, that is, there are 0.833 moles of ammonia (solute) per liter of solution. Then,


1.75LSolution * (0.833 molNH_3)/(1LSolution) = 1.46 mol

Step 2: Calculate the mass of ammonia

The molar mass of ammonia is 17.03 g/mol. The mass corresponding to 1.46 moles of ammonia is:


1.46 mol * (17.03g)/(mol) = 24.9 g

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