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What are the solutions of this quadratic equation?

What are the solutions of this quadratic equation?-example-1
User Elvie
by
8.4k points

1 Answer

1 vote

Answer:

B.

Explanation:


x^2-8x+97=0


x=(-(-8)\pm√((-8)^2-4*1*97))/(2*1)\left\{x=\left.\ (-b\pm√(b^2-4ac))/(2a)\right\}\right.


=(8\pm√(-324))/(2)


=(8\pm18i)/(2)\left\{i^2\right.=-1\Longrightarrow√(-1)=\left.\ i\right\}


\Rightarrow x_1=4-9i,x_2=4+9i


\therefore Choose\ B.

I hope this helps you

:)

User Jeffrey Basurto
by
8.9k points

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