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A 20-kilogram box is sitting on an inclined plane with a 30-degree slope. If the box is at rest, what is the force

on the box due to friction?

User RJV Kumar
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1 Answer

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Answer:

Step-by-step explanation:

The box is at rest because , the component of weight along the surface downwards is equal to frictional force .

frictional force = mgsinθ

= 20 x 9.8 sin 30

= 98 N .

User Optio
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