Question

The length of a rectangle is 5 cm longer than its width.

If the perimeter of the rectangle is 30 cm, find its area.

Answer 1

5

Explanation:

Okay, so P = perimeter, and the problem says P = 30

Let's call x the width, and y is the length.

In the perimeter formula, 2X + 2Y = P

so 2X + 2Y = 30

The problem also tells us that that x = y+5, so now let's do some substituting and replace X with Y+5

2(y+5) + 2Y = 30

2y+10 +2Y = 30

4y+10=30

-10. -10

4y=20

Y=5

TRIED MY BEST PRETTY SURE ITS RIGHT

Answer 2

Equation To write :2 {x+ ( x+5) }=30

Let's solve your equation step-by-step.

2(x+x+5)=30

Step 1: Simplify both sides of the equation.

2(x+x+5)=30

(2)(x)+(2)(x)+(2)(5)=30(Distribute)

2x+2x+10=30

(2x+2x)+(10)=30(Combine Like Terms)

4x+10=30

4x+10=30

Step 2: Subtract 10 from both sides.

4x+10−10=30−10

4x=20

Step 3: Divide both sides by 4.

4x

4

=

20

4

x=5

So... x+5=10.

Area =5x10=50 cm squared.