Final answer:
The mass of zinc sulfide produced from 0.250 g of zinc and 0.750 g of sulfur is 0.250 g.
Step-by-step explanation:
To determine the mass of zinc sulfide produced, we need to first identify the limiting reactant. The limiting reactant is the reactant that is completely consumed and determines the amount of product formed. We can determine the limiting reactant by calculating the number of moles of zinc and sulfur using their respective masses and molar masses. The molar ratio between zinc and sulfur in the balanced equation is 1:1, so whichever reactant has fewer moles will be the limiting reactant.
For zinc, we have 0.250 g and a molar mass of 65.38 g/mol, giving us 0.250 g / 65.38 g/mol = 0.00382 mol.
For sulfur, we have 0.750 g and a molar mass of 32.06 g/mol, giving us 0.750 g / 32.06 g/mol = 0.0234 mol.
Since zinc has fewer moles (0.00382 mol < 0.0234 mol), it is the limiting reactant. The molar ratio tells us that 1 mole of zinc reacts with 1 mole of sulfur to produce 1 mole of zinc sulfide. Therefore, the mass of zinc sulfide produced from 0.250 g of zinc is also 0.250 g.