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What is the concentration of a solution in which 0.99 g of KOH are dissolved in 500 mL?

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Answer:

.00352mol/L

Step-by-step explanation:

molarity (concentration) = number of moles / volume of solvent (in L)

M = .99g / 56.108‬g/mol / .5L

M = .0176mol / .5L

M = .00352mol/L

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