Question

If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol

Answer 1

`V_(2) = 29.28\,L`

Step-by-step explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

`(V_(1))/(n_(1)) = (V_(2))/(n_(2))`

`V_(2) = V_(1) \cdot \left((n_(2))/(n_(1)) \right)`

`V_(2) = (12.2\,L)\cdot \left((16.8\,moles)/(7\,moles) \right)`

`V_(2) = 29.28\,L`