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4. A steel plate that weighs 200 N and has a u with the asphalt of 0.6. If the steel plate is sliding along the asphalt (constant velocity), what is the force of friction present? Given Want Equation and
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11 votes
11 votes
4.

A steel plate that weighs 200 N and has a u with the asphalt of 0.6. If the steel
plate is sliding along the asphalt (constant velocity), what is the force of friction present?
Given
Want
Equation and solve

User Ruu
by
2.9k points

1 Answer

29 votes
29 votes

Answer:

120N

Step-by-step explanation:

The question gives us Mg = 200 N and in this equation Mg is equal to the normal force. Kinetic friction is calculated by normal force * coefficient of kinetic friction. Therefore kinetic friction = 200N * 0.6 = 120N

User Rinat Diushenov
by
3.3k points
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