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How do you find the area of triangle with a 99-degree angle and 11 Aas the adjacent sides?

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Answer:

Area = 59.8 sq units

Explanation:

There is a very convenient area formula for the area of a triangle given two sides and the included angle.

A = 1/2•a•b•sin C°

A = 1/2(11)(11)sin 99°

A = 59.8 sq units

How do you find the area of triangle with a 99-degree angle and 11 Aas the adjacent-example-1
User Hydradon
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