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An ideal gas, such as helium, is in a sealed container made of hard steel. If the container is heated, what would happen to the gas trapped inside the container?

Group of answer choices

The volume of the gas will decrease

The pressure of the gas will increase

The volume of the gas will increase

The pressure of the gas will decrease

2 Answers

1 vote

Answer: The volume of the container will decrease.

Step-by-step explanation:

User Shada
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Answer:

The correct answer is The pressure of the gas will increase

The volume of the gas will increase

Step-by-step explanation:

Step 1: Data given

The gas in a container is heated, this means the temperature increases

Suppose we start with a temperature of 100 K and a pressure of 1 atm and a volume of 1L

Step 2:

V1/T1= V2/T2

⇒V1 = the initial volume = 1L

⇒T1 = the initial temperature = 100 K

⇒V2 = the new volume = TO BE DETERMINED

⇒T2 = the increased temperature = 200 K

1/100 = V2 / 200

V2 = 2 L

This means when the temperature increases, the volume will increase

P1/T1 = P2/T2

⇒P1 = the initial pressure = 1 atm

⇒T1 = the initial temperature = 100 K

⇒P2 = the new pressure = TO BE DETERMINED

⇒T2 = the increased temperature = 200 K

1/100 = P2 / 200

P2 = 2 atm

This means when the temperature increases, the pressure will increase

The correct answer is The pressure of the gas will increase

The volume of the gas will increase

User Xdzc
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