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4. A steel plate that weighs 200 N and has a u with the asphalt of 0.6. If the steel plate is sliding along the asphalt (constant velocity), what is the force of friction present? Given Want Equation and
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4.

A steel plate that weighs 200 N and has a u with the asphalt of 0.6. If the steel
plate is sliding along the asphalt (constant velocity), what is the force of friction present?
Given
Want
Equation and solve

User Syd
by
3.8k points

1 Answer

5 votes

Answer:

120N

Step-by-step explanation:

The question gives us Mg = 200 N and in this equation Mg is equal to the normal force. Kinetic friction is calculated by normal force * coefficient of kinetic friction. Therefore kinetic friction = 200N * 0.6 = 120N

User Scorgn
by
3.4k points
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