Question

1 point

If the pressure in a cylinder is 1 atm and the volume is 0.725 liters, then
what is the pressure when the volume is decreased to .075 liters (at
constant temperature)? *
2.5 atm
5 atm
5 atm
9.7 atm
O
13.2 atm

Answer 1

9.7 atm.

Step-by-step explanation:

The following data were obtained from the question:

Initial pressure (P1) = 1 atm

Initial volume (V1) = 0.725 L

Final volume (V2) = 0.075 L

Final pressure (P2) =?

The final pressure can be obtained by using the Boyle's law equation since the temperature is constant. This is illustrated below:

P1V1 = P2V2

1 x 0.725 = P2 x 0.075

Divide both side by 0.075

P2 = 0.725 / 0.075

P2 = 9.7 atm.

Therefore, the new pressure is 9.7 atm.