Question

In the following reaction 6.13g of water (H2O) is produced the theoretical

yield of water (H2O) is 8.17g, what is the percent yield of water? *
C3H8+5 02 3 CO2 + 4 H2O

A) 85.0%
B) 72.0%
C) 75.0%
D) 67.0%

Answer 1

C = 75%

Step-by-step explanation:

Theoretical yield = 8.17g

Actual yield = 6.13g

To calculate the percentage yield of a compound in a reaction, we'll use the formula to calculate it

Percentage yield = (actual yield / theoretical yield) * 100

% yield = (6.13/8.17) * 100

Percentage yield = 0.7503 * 100

Percentage yield = 75.03%