Answer:
Option 2
Option 4
Option 5
Option 6
Explanation:
y is imaginary when the value under the radical is negative
x + 1 < 0
x < -1
2x - 12 < 0
2x < 12
x < 6
6 - x < 0
x > 6
x - 1 < 0
x < 1
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