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Find the limit as x approaches 25:
x-25
√x-5

User Ubica
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1 Answer

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x - 25 = (√x)^2 - 5^2 = (√x - 5)(√x + 5)

Then

(x - 25)/(√x - 5) = √x + 5

and as x approaches 25, we get a limit of √25 + 5 = 5 + 5 = 10.

User Andrzej Purtak
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