70.0k views
0 votes
Find the limit as x approaches 25:
x-25
√x-5

User Ubica
by
8.6k points

1 Answer

3 votes

x - 25 = (√x)^2 - 5^2 = (√x - 5)(√x + 5)

Then

(x - 25)/(√x - 5) = √x + 5

and as x approaches 25, we get a limit of √25 + 5 = 5 + 5 = 10.

User Andrzej Purtak
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories