Answer:third term=14 twelfth term=59
Explanation:
first term=a=4
Common difference=d=5
Second term=4+5=9
Third term=9+5=14
Using Tn=a+d(n-1)
T12=4+5(12-1)
T12=4+5x11
T12=4+55
T12=59
Twelveth term=59
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