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Find the exact value of T Image below

T= (tan(2z)+1)(2 cos(z)-1)/ y^ 2 -x^ 2 , where x = 9 , y = 41 and z = 30 degrees

please explain

Find the exact value of T Image below T= (tan(2z)+1)(2 cos(z)-1)/ y^ 2 -x^ 2 , where-example-1
User Iblazevic
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1 Answer

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Answer:

a) 1/800 or 0.00125

b) i) 0.0013

ii) 0.001

c) 60%

Explanation:

T = [tan(2×30)+1][2cos(30)-1] ÷ (y²-x²)

T = (tan60 + 1)(2cos30 - 1) ÷ (41² - 9²)

T = (sqrt(3) + 1)(sqrt(3) - 1) ÷ 1600

T = (3-1)/1600

T = 2/1600

T = 1/800

T = 0.00125

Error: 0.002 - 0.00125

0.00075

%error

0.00075/0.00125 × 100

60%

User William Thomas
by
7.9k points

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