Question

HELP ME PLEASE , ALOT OF POINTS, CHECK DOCUMENT! Show work

Answer 1

x = 8

Explanation:

log4(x - 6) + log4(x) = 2

log4[(x - 6) × x] = 2

x² - 6x = 4²

x² - 6x - 16 = 0

x² - 8x + 2x - 16 = 0

x(x - 8) + 2(x - 8) = 0

(x + 2)(x - 8) = 0

x = 8, -2

Log of negative numbers do not exist, so x is only 8

Answer 2

x=8

Explanation:

log4( x-6) +log4(x) = 2

We know that loga + log b = log (ab)

log4( x-6)(x) = 2

Raise each side to the base of 4

4^log4( x-6)(x) = 4^2

( x-6)(x) = 16

Distribute

x^2 -6x = 16

Subtract 16 from each side

x^2 -6x-16 = 0

Factor

(x-8) (x+2) =0

Using the zero product property

x-8=0 x+2 =0

x=8 x=-2

Checking, we cannot have the log of a negative number so -2 is not a solution