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A gas has a volume of 3.25 liters at 54 C and 231 kPa of pressure. At what temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa?

User Mike Spear
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1 Answer

3 votes

Answer: 318 K

Step-by-step explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,


(P_1V_1)/(T_1)=(P_2V_2)/(T_2)

where,


P_1 = initial pressure of gas = 231 kPa


P_2 = final pressure of gas = 168 kPa


V_1 = initial volume of gas = 3.25 L


V_2 = final volume of gas = 4.35 L


T_1 = initial temperature of gas =
54^oC=273+54=327K


T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:


(231* 3.25)/(327)=(168* 4.35)/(T_2)


T_2=318K

At 318 K of temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa

User Thomas Dussaut
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