Answer:
2.6 × 10³ g Al
74 mol O₂
Step-by-step explanation:
Aluminum oxide decomposes into aluminum and oxygen, according to the following balanced equation.
2 Al₂O₃ ⇒ 4 Al + 3 O₂
Step 1: Calculate the moles corresponding to 5.0 kg of aluminum oxide
The molar mass of aluminum oxide is 101.96 g/mol.
![5.0 * 10^(3) g * (1mol)/(101.96g) = 49mol](https://img.qammunity.org/2021/formulas/chemistry/college/7sj6w381w58f42m3n29tihsa4q0x47h8f6.png)
Step 2: Calculate the mass of aluminum formed
We will use the following relations.
- The molar ratio of Al₂O₃ to Al is 2:4
- The molar mass of Al is 26.98 g/mol
![49molAl_2O_3 * (4molAl)/(2molAl_2O_3) * (26.98gAl)/(1molAl) = 2.6 * 10^(3) gAl](https://img.qammunity.org/2021/formulas/chemistry/college/o9p7yr45dggcty7e02o35vec07dqdxjh2u.png)
Step 3: Calculate the moles of oxygen produced
The molar ratio of Al₂O₃ to O₂ is 2:3. Then,
![49molAl_2O_3 * (3molO_2)/(2molAl_2O_3) =74molO_2](https://img.qammunity.org/2021/formulas/chemistry/college/atnjoxwhe1s1okvsa2otg3ispci5pn0dyi.png)