Question

If a wiggling string has a natural frequency of 34.5 Hz to produce 4 harmonics, what is the period of the string?

Answer 1

`T = (1)/(f)`

And replacing we got:

`T = (1)/(34.5 Hz)= 0.0290 s`

And then we can conclude that with the conditions given the period of the string would be 0.0290 s

Explanation:

For this case we know the frequency associated to the 4 harmonic.

We know that by definition the frequency is the inverse of the period:

`f= (1)/(T)`

If we solve for the period we got:

`T = (1)/(f)`

And replacing we got:

`T = (1)/(34.5 Hz)= 0.0290 s`

And then we can conclude that with the conditions given the period of the string would be 0.0290 s