Question

How many moles of O2 are needed to react completely with 35 moles of FeCl3? 4FeCl3 + 3O2 > 2Fe2O3 + 3Cl2

Answer 1

`n_(O_2)=26.25molO_2`

Step-by-step explanation:

Hello,

In this case, given the reaction:

`4FeCl_3 + 3O_2 \rightarrow 2Fe_2O_3 + 6Cl_2`

Since oxygen and iron (III) chloride are in a 4:3 molar ratio, he required moles of oxygen to completely react with 35 moles of iron (III) chloride result:

`n_(O_2)=35molFeCl_3*(3molO_2)/(4molFeCl_3) \\\\n_(O_2)=26.25molO_2`

Best regards.

Answer 2

26 mol

Step-by-step explanation:

Step 1: Write the balanced equation

4 FeCl₃ + 3 O₂ ⇒ 2 Fe₂O₃ + 3 Cl₂

Step 2: Determine the appropriate molar ratio

The molar ratio of FeCl₃ to O₂ is 4:3.

Step 3: Use the determined molar ratio to calculate the moles of oxygen required to completely react with 35 moles of ferric chloride

`35molFeCl_3 * (3molO_2)/(4molFeCl_3) = 26molO_2`