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1 vote
Find the center and radius when x^2+y^2+4x-4y=17

2 Answers

4 votes

Answer:

Center: (-2,2)

Radius:5

Explanation:

The first step in this problem is to complete the square and to find the equation of this circle in standard form.


x^2+y^2+4x-4y=17 can be rearranged to be:


x^2+4x+y^2-4y=17

Now, you can begin to complete the square with both the x and the y:


(x^2+4x+4)-4+(y^2-4y+4)-4=17

Adding 8 to both sides and finishing the squares:


(x+2)^2+(y-2)^2=25
(x+2)^2+(y-2)^2=25

The coordinates of the center of the circle are (-2,2), and the radius is
√(25)=5. Hope this helps!

User Cgon
by
3.5k points
1 vote

Answer:

the center is (-2,2) and the radius is 5

User Andres SK
by
3.3k points