Question

A line includes the points (6,10) and (1,0) What is its equation in slope-intercept form?

Answer 1

The slope-intercept is
`y = 2x -2` .

Explanation:

-First, you need to find the slope by using the slope formula:

`m =(y_(2)-y_(1))/(x_(2)-x_(1))`

-Second, use both points (6, 10) and (1, 0) for the formula:

`m =(0-10)/(1-6)`

-Third, you solve:

`m =(0-10)/(1-6)`

`m = 2`

-Fourth, after you found the slope, you need to use the Point-slope form equation:

`y - y_(1) = m (x -x_(1))` (where
`m` represents the slope, and
`(x_(1),y_(1))` represents the first coordinate or the first point).

-Fifth, use the slope 2 and the first point (6, 10) for the Point-slope form equation:

`y - 10= 2 (x -6)`

-Sixth, you solve the equation to get the slope-intercept form:

`y - 10= 2 (x -6)`

`y -10 = 2x -12`

`y -10 +10 = 2x -12 +10`

`y = 2x -2`

So, therefore, the slope-intercept is
`y = 2x -2` .