Answer:
![m=13.1gO_2](https://img.qammunity.org/2021/formulas/chemistry/college/kcox1irprdhyf5g01ivk03wt47zhrh0osy.png)
Step-by-step explanation:
Hello,
In this case, by using the ideal gas equation, we first compute the moles of oxygen at the given volume, pressure and temperature:
![PV=nRT\\\\n=(PV)/(RT)=(2.0atm*5L)/(0.082(atm*L)/(mol*K)(25+273.15)K) =0.41mol](https://img.qammunity.org/2021/formulas/chemistry/college/219ukmqtb08lx5djpeh17psmy9iiywvge1.png)
Then, since molar mass of gaseous oxygen is 32 g/mol, we compute the contained mass in grams as shown below:
![m=0.41mol*(32g)/(1mol)\\\\m=13.1gO_2](https://img.qammunity.org/2021/formulas/chemistry/college/p8n1eo9xrnis53fc29stykzv6gvxfl6bkt.png)
Best regards.