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I have a 5 liter container of oxygen (O 2 ) gas at 2.0 atm and 25 0 C, what mass of gas is inside this

container in grams?

User Cquillen
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1 Answer

3 votes

Answer:


m=13.1gO_2

Step-by-step explanation:

Hello,

In this case, by using the ideal gas equation, we first compute the moles of oxygen at the given volume, pressure and temperature:


PV=nRT\\\\n=(PV)/(RT)=(2.0atm*5L)/(0.082(atm*L)/(mol*K)(25+273.15)K) =0.41mol

Then, since molar mass of gaseous oxygen is 32 g/mol, we compute the contained mass in grams as shown below:


m=0.41mol*(32g)/(1mol)\\\\m=13.1gO_2

Best regards.

User Sharafjaffri
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