Question

Which of the following is the graph of y = sin(0.5x)?

On a coordinate plane, a curve crosses the y-axis at (0, 0). It has a maximum of 1 and a minimum of negative 1. it goes through 2 cycles at 24 pi.
On a coordinate plane, a curve crosses the y-axis at (0, 0). It has a maximum of 1 and a minimum of negative 1. it goes through 2 cycles at 2 pi.
On a coordinate plane, a curve crosses the y-axis at (0, 0). It has a maximum of 1 and a minimum of negative 1. it goes through 1 cycle at 8 pi.
On a coordinate plane, a curve crosses the y-axis at (0, 0). It has a maximum of 1 and a minimum of negative 1. it goes through 2 cycles at 8 pi.

Answer 1

d

Explanation:

Answer 2

Answer: On a coordinate plane, a curve crosses the y-axis at (0, 0). It has a maximum of 1 and a minimum of negative 1. it goes through 2 cycles at 8 pi.

Explanation:

The function is y = sin(0.5*x)

We know that sin(0) = 0, so this graph must pass trough the point (0,0)

We know that the maximum of the sin(x) is 1, when x = pi/2. and the minimum is -1 when x = (3/2)*pi

but in our case the function is valuated in 0.5*x

then the maximum is when:

0.5*x = pi/2

x = pi/(2*0.5) = pi

and the minimum is when

0.5*x = (3/2)*pi

x = 3*pi

Now, knowing that sin(2*pi) = 0

The other 0 of the sin is when we have 0.5*x = 2*pi

x = 2*pi/0.5 = 4*pi

this means that in 4*pi we have one cycle, then in 8*pi we have tow cycles.

Then the correct option is:

"On a coordinate plane, a curve crosses the y-axis at (0, 0). It has a maximum of 1 and a minimum of negative 1. it goes through 2 cycles at 8 pi."