Question

A coil consists of 180 turns of wire. Each turn is a square of side d=30 cm, and a uniform magnetic field directed perpendicular to the plane of the coil is turned on. If the field changes linearly from 0 to 1.22 T in 0.06s, what is the magnitude of the induced force in the coil while the field is changing?

Answer 1

Emf induced i equal to 329.4 volt

Step-by-step explanation:

Note : Here i think we have to find emf induced in the coil

Number of turns in the coil N= 180

Sides of square d = 30 cm = 0.3 m

So area of the square
`A=0.3* 0.3=0.09m^2`

Magnetic field is changes from 0 to 1.22 T

Therefore
`dB=1.22-0=1.22T`

Time interval in changing the magnetic field dt = 0.06 sec

Induced emf is given by

`e=-N(d\Phi )/(dt)=-NA(dB)/(dt)`

`e=-180* 0.09* (1.22)/(0.06)=329.4volt`