9514 1404 393
Answer:
- 1/6
- 1/2
- 1/2
- 1/4
Explanation:
For independent events, P(A&B) = P(A) · P(B). Here, we have pairs of events, one of which is certain: P(B) = 1. This means the probability of the desired outcome (P(A&B)) is the probability of the uncertain outcome taken by itself (P(A)).
1. P(3) = 1/6 . . . . . . only one of the 6 outcomes is 3
2. P(odd) = 1/2 . . . . 3 of the 6 numbers are odd
3. P(tails) = 1/2 . . . . assuming a fair coin
4. P(tails&tails) = (1/2)(1/2) = 1/4 . . . . . . the unknown outcomes can be TT, TH, HT, or HH, all equally likely. P(TT) = 1/4.