Answer:
(a)1/6
(b)1/12
Explanation:
Given that the cubes are numbered from 1 to 6.
The possible outcomes are:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Total number of possible Outcomes=36
Part A
Probability that the sum of the number cubes is 7.
The outcomes that sums up to 7 are:
(1,6) (2,5) (3,4) (4,3) (5,2) (6,1)
Number of outcomes=6
Therefore:
P(sum of the number cubes is 7)=6/36=1/6
Part B
The sum of the number cubes is less than 4.
Outcomes in which the sum is less than 4 are:
(1,1) (1,2) (2,1)
Number of outcomes=3
Therefore:
P(sum of the number cubes is less than 4)=3/36=1/12