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What is the new temperature in Kelvin if a gas at 275 Kand 835 mmHg

expands to 2.1 atm if volume remains constant?
605.7 K
398.1 K
526.0 K
O
2.16K

What is the new temperature in Kelvin if a gas at 275 Kand 835 mmHg expands to 2.1 atm-example-1
User Pvorb
by
4.9k points

1 Answer

2 votes

Answer:

526 K

Step-by-step explanation:

Applying pressure law,

P/T = P'/T'...................... Equation 1

Where P = initial pressure of the gas, T = Initial temperature of the gas, P' = Final pressure the gas, T' = Final temperature of the gas.

make T' the subject of the equation

T' = TP'/P............. Equation 2

Given: T = 275 K, P = 835 mmHg, P' = 2.1 atm = (2.1×760) mmHg = 1596 mmHg.

Substitute these values into equation 2

T' = 275(1596)/835

T' = 438900/835

T' = 525.6

T' ≈ 526 K.

Hence the right option is 526 K

User Francesco Gualazzi
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4.6k points