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The zeroes of a cubic polynomial  x3 --  27 x  are  ---- , ---- and  -------... ( help plzz) ​

User Farwa
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1 Answer

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Answer:

The zeroes of a cubic polynomial
x^(3)-27\cdot x are
0,
-√(27) and
+√(27).

Explanation:

The zeroes of the third-order polynomial are obtained by factorization:


x^(3)-27\cdot x


x\cdot (x^(2)-27)


x\cdot (x+√(27))\cdot (x-√(27))

The zeroes of a cubic polynomial
x^(3)-27\cdot x are
0,
-√(27) and
+√(27).

User Hearty
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