Question

What is the product? StartFraction 2 a minus 7 Over a EndFraction times StartFraction 3 a squared Over 2 a squared minus 11 a + 14 EndFraction

Answer 1

the answer to this question is B.

Explanation:

Answer 2

The product is
`(3a)/(a-2)`.

Explanation:

The expression is:

`(2a-7)/(a)* (3a^(2))/(2a^(2)-11a+14)`

Simplify as follows:

`(2a-7)/(a)* (3a^(2))/(2a^(2)-11a+14)=(2a-7)* (3a)/(2a^(2)-7a-4a+14)`

`=(2a-7)* (3a)/(a(2a-7)-2(2a-7))\\\\=(2a-7)* (3a)/((a-2)(2a-7))\\\\=(3a)/(a-2)`

Thus, the product is
`(3a)/(a-2)`.